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# How to check if a directory exists in a Bash Script?

Checking if a directory exists or not can be easily done with the script below

if [ -d "$DIRECTORY_PATH" ]; then # If the$DIRECTORY_PATH exists, code inside the block will get executed
fi


Or to check if a directory doesn't exist:

if [ ! -d "$DIRECTORY_PATH" ]; then # If the$DIRECTORY_PATH does not exists, code inside the block will get executed
fi


Note that a the code inside the if block will still get executed if the folder was a symbolic link.

Also Note that, the "$DIRECTORY_PATH" is enclosed with double quotes. This is to handle cases where the directory name can have spaces and special characters(wildcard characters). Let's say you had created a symbolic link of a folder. ln -s "$DIRECTORY_PATH" "$SYMLINK_PATH"  Now if we check if the symbolic link, you will get an error rmdir: failed to remove 'symlink': Not a directory if [ -d "$SYMLINK_PATH" ]; then
rmdir "$SYMLINK_PATH" fi  So, to treat this edge case, we will have to handle symlink's condition as shown below. if [ -d "$DIRECTORY_PATH" ]; then
if [ -L "$DIRECTORY_PATH" ]; then # It is a symlink! # Symbolic link specific commands go here. rm "$DIRECTORY_PATH"
else
# It's a directory!
# Directory command goes here.
rmdir "\$DIRECTORY_PATH"
fi
fi


The above code is an ideal way to check if a path is a directory or not.